2(1/2x+1)=(-2+3x)-2(x-2)

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Solution for 2(1/2x+1)=(-2+3x)-2(x-2) equation: 



2(1/2x+1)=(-2+3x)-2(x-2)

We move all terms to the left:

2(1/2x+1)-((-2+3x)-2(x-2))=0



Domain of the equation: 2x+1)!=0

x∈R



We add all the numbers together, and all the variables

2(1/2x+1)-((3x-2)-2(x-2))=0

We multiply parentheses

2x-((3x-2)-2(x-2))+2=0



We calculate terms in parentheses: -((3x-2)-2(x-2)), so:

(3x-2)-2(x-2)

We multiply parentheses

(3x-2)-2x+4

We get rid of parentheses

3x-2x-2+4

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We get rid of parentheses

2x-x-2+2=0

We add all the numbers together, and all the variables

x=0

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