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2(1/2x+1)=-6x+3+4(2x+1)
We move all terms to the left:
2(1/2x+1)-(-6x+3+4(2x+1))=0
Domain of the equation: 2x+1)!=0We multiply parentheses
x∈R
2x-(-6x+3+4(2x+1))+2=0
We calculate terms in parentheses: -(-6x+3+4(2x+1)), so:We get rid of parentheses
-6x+3+4(2x+1)
determiningTheFunctionDomain -6x+4(2x+1)+3
We multiply parentheses
-6x+8x+4+3
We add all the numbers together, and all the variables
2x+7
Back to the equation:
-(2x+7)
2x-2x-7+2=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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