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2(1/2x+6)=2(3/2x+11)
We move all terms to the left:
2(1/2x+6)-(2(3/2x+11))=0
Domain of the equation: 2x+6)!=0
x∈R
Domain of the equation: 2x+11))!=0We multiply parentheses
x∈R
2x-(2(3/2x+11))+12=0
We multiply all the terms by the denominator
2x*2x+12*2x+11))-(2(3+11))=0
We add all the numbers together, and all the variables
2x*2x+12*2x+11))-(214)=0
We add all the numbers together, and all the variables
2x*2x+12*2x=0
Wy multiply elements
4x^2+24x=0
a = 4; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·4·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*4}=\frac{-48}{8} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*4}=\frac{0}{8} =0 $
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