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2(1/2x+6=3(x-3
We move all terms to the left:
2(1/2x+6-(3(x-3)=0
Domain of the equation: 2x+6-(3(x-3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x-(3(x-3)!=-6
x∈R
2(1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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