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2(1/2y+6)+y=12
We move all terms to the left:
2(1/2y+6)+y-(12)=0
Domain of the equation: 2y+6)!=0We add all the numbers together, and all the variables
y∈R
y+2(1/2y+6)-12=0
We multiply parentheses
y+2y+12-12=0
We add all the numbers together, and all the variables
3y=0
y=0/3
y=0
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