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2(1/3)x=2/9
We move all terms to the left:
2(1/3)x-(2/9)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(+1/3)x-(+2/9)=0
We multiply parentheses
2x^2-(+2/9)=0
We get rid of parentheses
2x^2-2/9=0
We multiply all the terms by the denominator
2x^2*9-2=0
Wy multiply elements
18x^2-2=0
a = 18; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·18·(-2)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*18}=\frac{-12}{36} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*18}=\frac{12}{36} =1/3 $
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