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2(1/4x-1)=2/3x+6
We move all terms to the left:
2(1/4x-1)-(2/3x+6)=0
Domain of the equation: 4x-1)!=0
x∈R
Domain of the equation: 3x+6)!=0We multiply parentheses
x∈R
2x-(2/3x+6)-2=0
We get rid of parentheses
2x-2/3x-6-2=0
We multiply all the terms by the denominator
2x*3x-6*3x-2*3x-2=0
Wy multiply elements
6x^2-18x-6x-2=0
We add all the numbers together, and all the variables
6x^2-24x-2=0
a = 6; b = -24; c = -2;
Δ = b2-4ac
Δ = -242-4·6·(-2)
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{39}}{2*6}=\frac{24-4\sqrt{39}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{39}}{2*6}=\frac{24+4\sqrt{39}}{12} $
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