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2(1/5)x=895
We move all terms to the left:
2(1/5)x-(895)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2(+1/5)x-895=0
We multiply parentheses
2x^2-895=0
a = 2; b = 0; c = -895;
Δ = b2-4ac
Δ = 02-4·2·(-895)
Δ = 7160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7160}=\sqrt{4*1790}=\sqrt{4}*\sqrt{1790}=2\sqrt{1790}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1790}}{2*2}=\frac{0-2\sqrt{1790}}{4} =-\frac{2\sqrt{1790}}{4} =-\frac{\sqrt{1790}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1790}}{2*2}=\frac{0+2\sqrt{1790}}{4} =\frac{2\sqrt{1790}}{4} =\frac{\sqrt{1790}}{2} $
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