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2(1/6+x)=2/3(x-1)
We move all terms to the left:
2(1/6+x)-(2/3(x-1))=0
Domain of the equation: 6+x)!=0
We move all terms containing x to the left, all other terms to the right
x)!=-6
x!=-6/1
x!=-6
x∈R
Domain of the equation: 3(x-1))!=0We add all the numbers together, and all the variables
x∈R
2(+x+1/6)-(2/3(x-1))=0
We multiply parentheses
2x-(2/3(x-1))+1/6*2=0
We calculate fractions
2x+()/(3(x-1))*6*2)+(3xx/(3(x-1))*6*2)=0
We calculate terms in parentheses: +()/(3(x-1))*6*2)+(3xx/(3(x-1))*6*2), so:
)/(3(x-1))*6*2)+(3xx/(3(x-1))*6*2
We can not solve this equation
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