2(10+2x)=4(2x-8)

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Solution for 2(10+2x)=4(2x-8) equation:



2(10+2x)=4(2x-8)
We move all terms to the left:
2(10+2x)-(4(2x-8))=0
We add all the numbers together, and all the variables
2(2x+10)-(4(2x-8))=0
We multiply parentheses
4x-(4(2x-8))+20=0
We calculate terms in parentheses: -(4(2x-8)), so:
4(2x-8)
We multiply parentheses
8x-32
Back to the equation:
-(8x-32)
We get rid of parentheses
4x-8x+32+20=0
We add all the numbers together, and all the variables
-4x+52=0
We move all terms containing x to the left, all other terms to the right
-4x=-52
x=-52/-4
x=+13

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