2(10+6x)+3(x-5)=35

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Solution for 2(10+6x)+3(x-5)=35 equation: 



2(10+6x)+3(x-5)=35

We move all terms to the left:

2(10+6x)+3(x-5)-(35)=0

We add all the numbers together, and all the variables

2(6x+10)+3(x-5)-35=0

We multiply parentheses

12x+3x+20-15-35=0

We add all the numbers together, and all the variables

15x-30=0

We move all terms containing x to the left, all other terms to the right

15x=30

x=30/15

x=2

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