2(10-13x)+9x=34x+71

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Solution for 2(10-13x)+9x=34x+71 equation: 



2(10-13x)+9x=34x+71

We move all terms to the left:

2(10-13x)+9x-(34x+71)=0

We add all the numbers together, and all the variables

2(-13x+10)+9x-(34x+71)=0

We add all the numbers together, and all the variables

9x+2(-13x+10)-(34x+71)=0

We multiply parentheses

9x-26x-(34x+71)+20=0

We get rid of parentheses

9x-26x-34x-71+20=0

We add all the numbers together, and all the variables

-51x-51=0

We move all terms containing x to the left, all other terms to the right

-51x=51

x=51/-51

x=-1

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