2(10-2f)=8(4-f)=

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Solution for 2(10-2f)=8(4-f)= equation:



2(10-2f)=8(4-f)=
We move all terms to the left:
2(10-2f)-(8(4-f))=0
We add all the numbers together, and all the variables
2(-2f+10)-(8(-1f+4))=0
We multiply parentheses
-4f-(8(-1f+4))+20=0
We calculate terms in parentheses: -(8(-1f+4)), so:
8(-1f+4)
We multiply parentheses
-8f+32
Back to the equation:
-(-8f+32)
We get rid of parentheses
-4f+8f-32+20=0
We add all the numbers together, and all the variables
4f-12=0
We move all terms containing f to the left, all other terms to the right
4f=12
f=12/4
f=3

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