2(10-2f)=8(4-f0

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Solution for 2(10-2f)=8(4-f0 equation: 



2(10-2f)=8(4-f0

We move all terms to the left:

2(10-2f)-(8(4-f0)=0

We add all the numbers together, and all the variables

2(-2f+10)-(8(-1f+4)=0

We multiply parentheses

-4f-(8(-1f+4)+20=0

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