2(10-2i)=4(2i+8)

Solution for 2(10-2i)=4(2i+8) equation:

2(10-2i)=4(2i+8)

We move all terms to the left:

2(10-2i)-(4(2i+8))=0

We add all the numbers together, and all the variables

2(-2i+10)-(4(2i+8))=0

We multiply parentheses

-4i-(4(2i+8))+20=0


We calculate terms in parentheses: -(4(2i+8)), so:

4(2i+8)

We multiply parentheses

8i+32

Back to the equation:

-(8i+32)


We get rid of parentheses

-4i-8i-32+20=0

We add all the numbers together, and all the variables

-12i-12=0

We move all terms containing i to the left, all other terms to the right

-12i=12

i=12/-12

i=-1