2(10-3b-c)+2b+4c=14

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Solution for 2(10-3b-c)+2b+4c=14 equation:


Simplifying
2(10 + -3b + -1c) + 2b + 4c = 14
(10 * 2 + -3b * 2 + -1c * 2) + 2b + 4c = 14
(20 + -6b + -2c) + 2b + 4c = 14

Reorder the terms:
20 + -6b + 2b + -2c + 4c = 14

Combine like terms: -6b + 2b = -4b
20 + -4b + -2c + 4c = 14

Combine like terms: -2c + 4c = 2c
20 + -4b + 2c = 14

Solving
20 + -4b + 2c = 14

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -4b + -20 + 2c = 14 + -20

Reorder the terms:
20 + -20 + -4b + 2c = 14 + -20

Combine like terms: 20 + -20 = 0
0 + -4b + 2c = 14 + -20
-4b + 2c = 14 + -20

Combine like terms: 14 + -20 = -6
-4b + 2c = -6

Add '-2c' to each side of the equation.
-4b + 2c + -2c = -6 + -2c

Combine like terms: 2c + -2c = 0
-4b + 0 = -6 + -2c
-4b = -6 + -2c

Divide each side by '-4'.
b = 1.5 + 0.5c

Simplifying
b = 1.5 + 0.5c

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