2(10-4b)+4b=12

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Solution for 2(10-4b)+4b=12 equation:



2(10-4b)+4b=12
We move all terms to the left:
2(10-4b)+4b-(12)=0
We add all the numbers together, and all the variables
2(-4b+10)+4b-12=0
We add all the numbers together, and all the variables
4b+2(-4b+10)-12=0
We multiply parentheses
4b-8b+20-12=0
We add all the numbers together, and all the variables
-4b+8=0
We move all terms containing b to the left, all other terms to the right
-4b=-8
b=-8/-4
b=+2

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