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2(10-x)+9=7x-2(x-4)
We move all terms to the left:
2(10-x)+9-(7x-2(x-4))=0
We add all the numbers together, and all the variables
2(-1x+10)-(7x-2(x-4))+9=0
We multiply parentheses
-2x-(7x-2(x-4))+20+9=0
We calculate terms in parentheses: -(7x-2(x-4)), so:We add all the numbers together, and all the variables
7x-2(x-4)
We multiply parentheses
7x-2x+8
We add all the numbers together, and all the variables
5x+8
Back to the equation:
-(5x+8)
-2x-(5x+8)+29=0
We get rid of parentheses
-2x-5x-8+29=0
We add all the numbers together, and all the variables
-7x+21=0
We move all terms containing x to the left, all other terms to the right
-7x=-21
x=-21/-7
x=+3
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