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2(10g-6)=4(5g+3)
We move all terms to the left:
2(10g-6)-(4(5g+3))=0
We multiply parentheses
20g-(4(5g+3))-12=0
We calculate terms in parentheses: -(4(5g+3)), so:We get rid of parentheses
4(5g+3)
We multiply parentheses
20g+12
Back to the equation:
-(20g+12)
20g-20g-12-12=0
We add all the numbers together, and all the variables
-24!=0
There is no solution for this equation
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