2(10x-10)-2=58

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Solution for 2(10x-10)-2=58 equation: 



2(10x-10)-2=58

We move all terms to the left:

2(10x-10)-2-(58)=0

We add all the numbers together, and all the variables

2(10x-10)-60=0

We multiply parentheses

20x-20-60=0

We add all the numbers together, and all the variables

20x-80=0

We move all terms containing x to the left, all other terms to the right

20x=80

x=80/20

x=4

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