2(10x-5)-6=4x+32

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Solution for 2(10x-5)-6=4x+32 equation: 



2(10x-5)-6=4x+32

We move all terms to the left:

2(10x-5)-6-(4x+32)=0

We multiply parentheses

20x-(4x+32)-10-6=0

We get rid of parentheses

20x-4x-32-10-6=0

We add all the numbers together, and all the variables

16x-48=0

We move all terms containing x to the left, all other terms to the right

16x=48

x=48/16

x=3

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