2(10z+4)-7=-4(-5z+5)21

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Solution for 2(10z+4)-7=-4(-5z+5)21 equation: 



2(10z+4)-7=-4(-5z+5)21

We move all terms to the left:

2(10z+4)-7-(-4(-5z+5)21)=0

We multiply parentheses

20z-(-4(-5z+5)21)+8-7=0



We calculate terms in parentheses: -(-4(-5z+5)21), so:

-4(-5z+5)21

We multiply parentheses

420z-420

Back to the equation:

-(420z-420)



We add all the numbers together, and all the variables

20z-(420z-420)+1=0

We get rid of parentheses

20z-420z+420+1=0

We add all the numbers together, and all the variables

-400z+421=0

We move all terms containing z to the left, all other terms to the right

-400z=-421

z=-421/-400

z=1+21/400

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