2(10z-5)+7(3+z)=308

Solution for 2(10z-5)+7(3+z)=308 equation:

2(10z-5)+7(3+z)=308

We simplify the equation to the form, which is simple to understand 
2(10z-5)+7(3+z)=308

Reorder the terms in parentheses
+(+20z-10)+7*(3+z)=308

Remove unnecessary parentheses
+20z-10+7+*(+3+z+)=+308

Reorder the terms in parentheses
+20z-10+(+21+7z)=308

Remove unnecessary parentheses
+20z-10+21+7z=+308

We move all terms containing z to the left and all other terms to the right. 
+20z+7z=+308+10-21

We simplify left and right side of the equation. 
+27z=+297

We divide both sides of the equation by 27 to get z. 
z=11