2(10z-6)=20z-12

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Solution for 2(10z-6)=20z-12 equation: 



2(10z-6)=20z-12

We move all terms to the left:

2(10z-6)-(20z-12)=0

We multiply parentheses

20z-(20z-12)-12=0

We get rid of parentheses

20z-20z+12-12=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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