2(12+2z)=68

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Solution for 2(12+2z)=68 equation:



2(12+2z)=68
We move all terms to the left:
2(12+2z)-(68)=0
We add all the numbers together, and all the variables
2(2z+12)-68=0
We multiply parentheses
4z+24-68=0
We add all the numbers together, and all the variables
4z-44=0
We move all terms containing z to the left, all other terms to the right
4z=44
z=44/4
z=11

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