2(12+2z)=68

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Solution for 2(12+2z)=68 equation: 



2(12+2z)=68

We move all terms to the left:

2(12+2z)-(68)=0

We add all the numbers together, and all the variables

2(2z+12)-68=0

We multiply parentheses

4z+24-68=0

We add all the numbers together, and all the variables

4z-44=0

We move all terms containing z to the left, all other terms to the right

4z=44

z=44/4

z=11

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