2(12+6c)=4(4c+14)

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Solution for 2(12+6c)=4(4c+14) equation:



2(12+6c)=4(4c+14)
We move all terms to the left:
2(12+6c)-(4(4c+14))=0
We add all the numbers together, and all the variables
2(6c+12)-(4(4c+14))=0
We multiply parentheses
12c-(4(4c+14))+24=0
We calculate terms in parentheses: -(4(4c+14)), so:
4(4c+14)
We multiply parentheses
16c+56
Back to the equation:
-(16c+56)
We get rid of parentheses
12c-16c-56+24=0
We add all the numbers together, and all the variables
-4c-32=0
We move all terms containing c to the left, all other terms to the right
-4c=32
c=32/-4
c=-8

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