2(12-2c)=3(-c)

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Solution for 2(12-2c)=3(-c) equation:



2(12-2c)=3(-c)
We move all terms to the left:
2(12-2c)-(3(-c))=0
We add all the numbers together, and all the variables
2(-2c+12)-(3(-1c))=0
We multiply parentheses
-4c-(3(-1c))+24=0
We calculate terms in parentheses: -(3(-1c)), so:
3(-1c)
We multiply parentheses
-3c
Back to the equation:
-(-3c)
We get rid of parentheses
-4c+3c+24=0
We add all the numbers together, and all the variables
-1c+24=0
We move all terms containing c to the left, all other terms to the right
-c=-24
c=-24/-1
c=+24

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