2(12-2c)=3(-c)

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Solution for 2(12-2c)=3(-c) equation: 



2(12-2c)=3(-c)

We move all terms to the left:

2(12-2c)-(3(-c))=0

We add all the numbers together, and all the variables

2(-2c+12)-(3(-1c))=0

We multiply parentheses

-4c-(3(-1c))+24=0



We calculate terms in parentheses: -(3(-1c)), so:

3(-1c)

We multiply parentheses

-3c

Back to the equation:

-(-3c)



We get rid of parentheses

-4c+3c+24=0

We add all the numbers together, and all the variables

-1c+24=0

We move all terms containing c to the left, all other terms to the right

-c=-24

c=-24/-1

c=+24

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