2(12-3x)=9(7x+18)

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Solution for 2(12-3x)=9(7x+18) equation: 



2(12-3x)=9(7x+18)

We move all terms to the left:

2(12-3x)-(9(7x+18))=0

We add all the numbers together, and all the variables

2(-3x+12)-(9(7x+18))=0

We multiply parentheses

-6x-(9(7x+18))+24=0



We calculate terms in parentheses: -(9(7x+18)), so:

9(7x+18)

We multiply parentheses

63x+162

Back to the equation:

-(63x+162)



We get rid of parentheses

-6x-63x-162+24=0

We add all the numbers together, and all the variables

-69x-138=0

We move all terms containing x to the left, all other terms to the right

-69x=138

x=138/-69

x=-2

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