2(12-k)-(k-3)=8(2-3k)-3(5-6k)

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Solution for 2(12-k)-(k-3)=8(2-3k)-3(5-6k) equation: 



2(12-k)-(k-3)=8(2-3k)-3(5-6k)

We move all terms to the left:

2(12-k)-(k-3)-(8(2-3k)-3(5-6k))=0

We add all the numbers together, and all the variables

2(-1k+12)-(k-3)-(8(-3k+2)-3(-6k+5))=0

We multiply parentheses

-2k-(k-3)-(8(-3k+2)-3(-6k+5))+24=0

We get rid of parentheses

-2k-k-(8(-3k+2)-3(-6k+5))+3+24=0



We calculate terms in parentheses: -(8(-3k+2)-3(-6k+5)), so:

8(-3k+2)-3(-6k+5)

We multiply parentheses

-24k+18k+16-15

We add all the numbers together, and all the variables

-6k+1

Back to the equation:

-(-6k+1)



We add all the numbers together, and all the variables

-3k-(-6k+1)+27=0

We get rid of parentheses

-3k+6k-1+27=0

We add all the numbers together, and all the variables

3k+26=0

We move all terms containing k to the left, all other terms to the right

3k=-26

k=-26/3

k=-8+2/3

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