2(12x-40)=2-2(x+6)

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Solution for 2(12x-40)=2-2(x+6) equation: 



2(12x-40)=2-2(x+6)

We move all terms to the left:

2(12x-40)-(2-2(x+6))=0

We multiply parentheses

24x-(2-2(x+6))-80=0



We calculate terms in parentheses: -(2-2(x+6)), so:

2-2(x+6)

determiningTheFunctionDomain
-2(x+6)+2

We multiply parentheses

-2x-12+2

We add all the numbers together, and all the variables

-2x-10

Back to the equation:

-(-2x-10)



We get rid of parentheses

24x+2x+10-80=0

We add all the numbers together, and all the variables

26x-70=0

We move all terms containing x to the left, all other terms to the right

26x=70

x=70/26

x=2+9/13

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