2(14x-11)=40x-(2x-5)

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Solution for 2(14x-11)=40x-(2x-5) equation: 



2(14x-11)=40x-(2x-5)

We move all terms to the left:

2(14x-11)-(40x-(2x-5))=0

We multiply parentheses

28x-(40x-(2x-5))-22=0



We calculate terms in parentheses: -(40x-(2x-5)), so:

40x-(2x-5)

We get rid of parentheses

40x-2x+5

We add all the numbers together, and all the variables

38x+5

Back to the equation:

-(38x+5)



We get rid of parentheses

28x-38x-5-22=0

We add all the numbers together, and all the variables

-10x-27=0

We move all terms containing x to the left, all other terms to the right

-10x=27

x=27/-10

x=-2+7/10

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