2(15-2y)=2(5y+1)-7(2y-4)

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Solution for 2(15-2y)=2(5y+1)-7(2y-4) equation: 



2(15-2y)=2(5y+1)-7(2y-4)

We move all terms to the left:

2(15-2y)-(2(5y+1)-7(2y-4))=0

We add all the numbers together, and all the variables

2(-2y+15)-(2(5y+1)-7(2y-4))=0

We multiply parentheses

-4y-(2(5y+1)-7(2y-4))+30=0



We calculate terms in parentheses: -(2(5y+1)-7(2y-4)), so:

2(5y+1)-7(2y-4)

We multiply parentheses

10y-14y+2+28

We add all the numbers together, and all the variables

-4y+30

Back to the equation:

-(-4y+30)



We get rid of parentheses

-4y+4y-30+30=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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