2(15c+8)=9(2c+4)-(3c+20)

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Solution for 2(15c+8)=9(2c+4)-(3c+20) equation: 



2(15c+8)=9(2c+4)-(3c+20)

We move all terms to the left:

2(15c+8)-(9(2c+4)-(3c+20))=0

We multiply parentheses

30c-(9(2c+4)-(3c+20))+16=0



We calculate terms in parentheses: -(9(2c+4)-(3c+20)), so:

9(2c+4)-(3c+20)

We multiply parentheses

18c-(3c+20)+36

We get rid of parentheses

18c-3c-20+36

We add all the numbers together, and all the variables

15c+16

Back to the equation:

-(15c+16)



We get rid of parentheses

30c-15c-16+16=0

We add all the numbers together, and all the variables

15c=0

c=0/15

c=0

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