2(16-2b)+4b=32

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Solution for 2(16-2b)+4b=32 equation: 



2(16-2b)+4b=32

We move all terms to the left:

2(16-2b)+4b-(32)=0

We add all the numbers together, and all the variables

2(-2b+16)+4b-32=0

We add all the numbers together, and all the variables

4b+2(-2b+16)-32=0

We multiply parentheses

4b-4b+32-32=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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