2(16y-5)-6=5(3y+3)-23

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Solution for 2(16y-5)-6=5(3y+3)-23 equation: 



2(16y-5)-6=5(3y+3)-23

We move all terms to the left:

2(16y-5)-6-(5(3y+3)-23)=0

We multiply parentheses

32y-(5(3y+3)-23)-10-6=0



We calculate terms in parentheses: -(5(3y+3)-23), so:

5(3y+3)-23

We multiply parentheses

15y+15-23

We add all the numbers together, and all the variables

15y-8

Back to the equation:

-(15y-8)



We add all the numbers together, and all the variables

32y-(15y-8)-16=0

We get rid of parentheses

32y-15y+8-16=0

We add all the numbers together, and all the variables

17y-8=0

We move all terms containing y to the left, all other terms to the right

17y=8

y=8/17

y=8/17

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