2(1b-3)+5=3(1b-1)

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Solution for 2(1b-3)+5=3(1b-1) equation: 



2(1b-3)+5=3(1b-1)

We move all terms to the left:

2(1b-3)+5-(3(1b-1))=0

We add all the numbers together, and all the variables

2(b-3)-(3(b-1))+5=0

We multiply parentheses

2b-(3(b-1))-6+5=0



We calculate terms in parentheses: -(3(b-1)), so:

3(b-1)

We multiply parentheses

3b-3

Back to the equation:

-(3b-3)



We add all the numbers together, and all the variables

2b-(3b-3)-1=0

We get rid of parentheses

2b-3b+3-1=0

We add all the numbers together, and all the variables

-1b+2=0

We move all terms containing b to the left, all other terms to the right

-b=-2

b=-2/-1

b=+2

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