2(1c+3)+5c=15-1(2c+18)

Solution for 2(1c+3)+5c=15-1(2c+18) equation:

Simplifying
2(1c + 3) + 5c = 15 + -1(2c + 18)

Reorder the terms:
2(3 + 1c) + 5c = 15 + -1(2c + 18)
(3 * 2 + 1c * 2) + 5c = 15 + -1(2c + 18)
(6 + 2c) + 5c = 15 + -1(2c + 18)

Combine like terms: 2c + 5c = 7c
6 + 7c = 15 + -1(2c + 18)

Reorder the terms:
6 + 7c = 15 + -1(18 + 2c)
6 + 7c = 15 + (18 * -1 + 2c * -1)
6 + 7c = 15 + (-18 + -2c)

Combine like terms: 15 + -18 = -3
6 + 7c = -3 + -2c

Solving
6 + 7c = -3 + -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
6 + 7c + 2c = -3 + -2c + 2c

Combine like terms: 7c + 2c = 9c
6 + 9c = -3 + -2c + 2c

Combine like terms: -2c + 2c = 0
6 + 9c = -3 + 0
6 + 9c = -3

Add '-6' to each side of the equation.
6 + -6 + 9c = -3 + -6

Combine like terms: 6 + -6 = 0
0 + 9c = -3 + -6
9c = -3 + -6

Combine like terms: -3 + -6 = -9
9c = -9

Divide each side by '9'.
c = -1

Simplifying
c = -1