2(1d+5)=3(1d-2)

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Solution for 2(1d+5)=3(1d-2) equation:


Simplifying
2(1d + 5) = 3(1d + -2)

Reorder the terms:
2(5 + 1d) = 3(1d + -2)
(5 * 2 + 1d * 2) = 3(1d + -2)
(10 + 2d) = 3(1d + -2)

Reorder the terms:
10 + 2d = 3(-2 + 1d)
10 + 2d = (-2 * 3 + 1d * 3)
10 + 2d = (-6 + 3d)

Solving
10 + 2d = -6 + 3d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3d' to each side of the equation.
10 + 2d + -3d = -6 + 3d + -3d

Combine like terms: 2d + -3d = -1d
10 + -1d = -6 + 3d + -3d

Combine like terms: 3d + -3d = 0
10 + -1d = -6 + 0
10 + -1d = -6

Add '-10' to each side of the equation.
10 + -10 + -1d = -6 + -10

Combine like terms: 10 + -10 = 0
0 + -1d = -6 + -10
-1d = -6 + -10

Combine like terms: -6 + -10 = -16
-1d = -16

Divide each side by '-1'.
d = 16

Simplifying
d = 16

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