2(1s+3)+(4s-5)=1s

Solution for 2(1s+3)+(4s-5)=1s equation:

Simplifying
2(1s + 3) + (4s + -5) = 1s

Reorder the terms:
2(3 + 1s) + (4s + -5) = 1s
(3 * 2 + 1s * 2) + (4s + -5) = 1s
(6 + 2s) + (4s + -5) = 1s

Reorder the terms:
6 + 2s + (-5 + 4s) = 1s

Remove parenthesis around (-5 + 4s)
6 + 2s + -5 + 4s = 1s

Reorder the terms:
6 + -5 + 2s + 4s = 1s

Combine like terms: 6 + -5 = 1
1 + 2s + 4s = 1s

Combine like terms: 2s + 4s = 6s
1 + 6s = 1s

Solving
1 + 6s = 1s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-1s' to each side of the equation.
1 + 6s + -1s = 1s + -1s

Combine like terms: 6s + -1s = 5s
1 + 5s = 1s + -1s

Combine like terms: 1s + -1s = 0
1 + 5s = 0

Add '-1' to each side of the equation.
1 + -1 + 5s = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 5s = 0 + -1
5s = 0 + -1

Combine like terms: 0 + -1 = -1
5s = -1

Divide each side by '5'.
s = -0.2

Simplifying
s = -0.2