2(1t+3t)=32

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Solution for 2(1t+3t)=32 equation: 



2(1t+3t)=32

We move all terms to the left:

2(1t+3t)-(32)=0

We add all the numbers together, and all the variables

2(+4t)-32=0

We multiply parentheses

8t-32=0

We move all terms containing t to the left, all other terms to the right

8t=32

t=32/8

t=4

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