2(1t-6)=-32

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Solution for 2(1t-6)=-32 equation: 


t in (-oo:+oo)

2*(1*t-6) = -32 // + 32

2*(1*t-6)+32 = 0

2*(t-6)+32 = 0

2*(t-6)+32 = 0

2*t+20 = 0

2*t+20 = 0

2*t+20 = 0 // - 20

2*t = -20 // : 2

t = -20/2

t = -10

t = -10

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