2(1x+5)-7=3(x-2)

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Solution for 2(1x+5)-7=3(x-2) equation:



2(1x+5)-7=3(x-2)
We move all terms to the left:
2(1x+5)-7-(3(x-2))=0
We add all the numbers together, and all the variables
2(x+5)-(3(x-2))-7=0
We multiply parentheses
2x-(3(x-2))+10-7=0
We calculate terms in parentheses: -(3(x-2)), so:
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
We add all the numbers together, and all the variables
2x-(3x-6)+3=0
We get rid of parentheses
2x-3x+6+3=0
We add all the numbers together, and all the variables
-1x+9=0
We move all terms containing x to the left, all other terms to the right
-x=-9
x=-9/-1
x=+9

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