2(1x-3)=3(1x+1)-22

Solution for 2(1x-3)=3(1x+1)-22 equation:

2(1x-3)=3(1x+1)-22

We move all terms to the left:

2(1x-3)-(3(1x+1)-22)=0

We add all the numbers together, and all the variables

2(x-3)-(3(x+1)-22)=0

We multiply parentheses

2x-(3(x+1)-22)-6=0


We calculate terms in parentheses: -(3(x+1)-22), so:

3(x+1)-22

We multiply parentheses

3x+3-22

We add all the numbers together, and all the variables

3x-19

Back to the equation:

-(3x-19)


We get rid of parentheses

2x-3x+19-6=0

We add all the numbers together, and all the variables

-1x+13=0

We move all terms containing x to the left, all other terms to the right

-x=-13

x=-13/-1

x=+13