2(1x-8)+1x=3(x-6)+2

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Solution for 2(1x-8)+1x=3(x-6)+2 equation: 


Simplifying
2(1x + -8) + 1x = 3(x + -6) + 2

Reorder the terms:
2(-8 + 1x) + 1x = 3(x + -6) + 2
(-8 * 2 + 1x * 2) + 1x = 3(x + -6) + 2
(-16 + 2x) + 1x = 3(x + -6) + 2

Combine like terms: 2x + 1x = 3x
-16 + 3x = 3(x + -6) + 2

Reorder the terms:
-16 + 3x = 3(-6 + x) + 2
-16 + 3x = (-6 * 3 + x * 3) + 2
-16 + 3x = (-18 + 3x) + 2

Reorder the terms:
-16 + 3x = -18 + 2 + 3x

Combine like terms: -18 + 2 = -16
-16 + 3x = -16 + 3x

Add '16' to each side of the equation.
-16 + 16 + 3x = -16 + 16 + 3x

Combine like terms: -16 + 16 = 0
0 + 3x = -16 + 16 + 3x
3x = -16 + 16 + 3x

Combine like terms: -16 + 16 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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