2(1y+3)=4y+8

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Solution for 2(1y+3)=4y+8 equation: 



2(1y+3)=4y+8

We move all terms to the left:

2(1y+3)-(4y+8)=0

We add all the numbers together, and all the variables

2(y+3)-(4y+8)=0

We multiply parentheses

2y-(4y+8)+6=0

We get rid of parentheses

2y-4y-8+6=0

We add all the numbers together, and all the variables

-2y-2=0

We move all terms containing y to the left, all other terms to the right

-2y=2

y=2/-2

y=-1

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