2(2+-3)=6(r+2)

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Solution for 2(2+-3)=6(r+2) equation: 



2(2+-3)=6(r+2)

We move all terms to the left:

2(2+-3)-(6(r+2))=0

We add all the numbers together, and all the variables

-(6(r+2))+2(-1)=0

We add all the numbers together, and all the variables

-(6(r+2))-2=0



We calculate terms in parentheses: -(6(r+2)), so:

6(r+2)

We multiply parentheses

6r+12

Back to the equation:

-(6r+12)



We get rid of parentheses

-6r-12-2=0

We add all the numbers together, and all the variables

-6r-14=0

We move all terms containing r to the left, all other terms to the right

-6r=14

r=14/-6

r=-2+1/3

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