2(2+22)=4(s+12)

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Solution for 2(2+22)=4(s+12) equation:


Simplifying
2(2 + 22) = 4(s + 12)

Combine like terms: 2 + 22 = 24
2(24) = 4(s + 12)

Multiply 2 * 24
48 = 4(s + 12)

Reorder the terms:
48 = 4(12 + s)
48 = (12 * 4 + s * 4)
48 = (48 + 4s)

Add '-48' to each side of the equation.
48 + -48 = 48 + -48 + 4s

Combine like terms: 48 + -48 = 0
0 = 48 + -48 + 4s

Combine like terms: 48 + -48 = 0
0 = 0 + 4s
0 = 4s

Solving
0 = 4s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-4s' to each side of the equation.
0 + -4s = 4s + -4s
Remove the zero:
-4s = 4s + -4s

Combine like terms: 4s + -4s = 0
-4s = 0

Divide each side by '-4'.
s = 0

Simplifying
s = 0

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