2(2+2m)=-5m-(3-2m)

Solution for 2(2+2m)=-5m-(3-2m) equation:

2(2+2m)=-5m-(3-2m)

We move all terms to the left:

2(2+2m)-(-5m-(3-2m))=0

We add all the numbers together, and all the variables

2(2m+2)-(-5m-(-2m+3))=0

We multiply parentheses

4m-(-5m-(-2m+3))+4=0


We calculate terms in parentheses: -(-5m-(-2m+3)), so:

-5m-(-2m+3)

We get rid of parentheses

-5m+2m-3

We add all the numbers together, and all the variables

-3m-3

Back to the equation:

-(-3m-3)


We get rid of parentheses

4m+3m+3+4=0

We add all the numbers together, and all the variables

7m+7=0

We move all terms containing m to the left, all other terms to the right

7m=-7

m=-7/7

m=-1