2(2+3)-7x=23-5(x+3x)

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Solution for 2(2+3)-7x=23-5(x+3x) equation: 



2(2+3)-7x=23-5(x+3x)

We move all terms to the left:

2(2+3)-7x-(23-5(x+3x))=0

We add all the numbers together, and all the variables

-7x-(23-5(+4x))+25=0



We calculate terms in parentheses: -(23-5(+4x)), so:

23-5(+4x)

determiningTheFunctionDomain
-5(+4x)+23

We multiply parentheses

-20x+23

Back to the equation:

-(-20x+23)



We get rid of parentheses

-7x+20x-23+25=0

We add all the numbers together, and all the variables

13x+2=0

We move all terms containing x to the left, all other terms to the right

13x=-2

x=-2/13

x=-2/13

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