2(2+3x)-2x=2(10-2x)

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Solution for 2(2+3x)-2x=2(10-2x) equation: 



2(2+3x)-2x=2(10-2x)

We move all terms to the left:

2(2+3x)-2x-(2(10-2x))=0

We add all the numbers together, and all the variables

2(3x+2)-2x-(2(-2x+10))=0

We add all the numbers together, and all the variables

-2x+2(3x+2)-(2(-2x+10))=0

We multiply parentheses

-2x+6x-(2(-2x+10))+4=0



We calculate terms in parentheses: -(2(-2x+10)), so:

2(-2x+10)

We multiply parentheses

-4x+20

Back to the equation:

-(-4x+20)



We add all the numbers together, and all the variables

4x-(-4x+20)+4=0

We get rid of parentheses

4x+4x-20+4=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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